Base | Representation |
---|---|
bin | 11001101101111111110001… |
… | …010100010001010101101001 |
3 | 112211111101212121211200011102 |
4 | 121231333301110101111221 |
5 | 104311211400131104423 |
6 | 1040322535141011145 |
7 | 32553034053250151 |
oct | 3155776124212551 |
9 | 484441777750142 |
10 | 113112012363113 |
11 | 3304a598178195 |
12 | 10829a480b3ab5 |
13 | 4b165561b395a |
14 | 1dd09173b3761 |
15 | d12482a54c28 |
hex | 66dff1511569 |
113112012363113 has 2 divisors, whose sum is σ = 113112012363114. Its totient is φ = 113112012363112.
The previous prime is 113112012363013. The next prime is 113112012363121. The reversal of 113112012363113 is 311363210211311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92762864297104 + 20349148066009 = 9631348^2 + 4511003^2 .
It is a cyclic number.
It is not a de Polignac number, because 113112012363113 - 238 = 112837134456169 is a prime.
It is not a weakly prime, because it can be changed into another prime (113112012363013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556006181556 + 56556006181557.
It is an arithmetic number, because the mean of its divisors is an integer number (56556006181557).
Almost surely, 2113112012363113 is an apocalyptic number.
It is an amenable number.
113112012363113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113112012363113 is an equidigital number, since it uses as much as digits as its factorization.
113112012363113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 29.
Adding to 113112012363113 its reverse (311363210211311), we get a palindrome (424475222574424).
The spelling of 113112012363113 in words is "one hundred thirteen trillion, one hundred twelve billion, twelve million, three hundred sixty-three thousand, one hundred thirteen".
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