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113112100133 = 179463703123
BaseRepresentation
bin110100101011000000…
…0011010110100100101
3101210221222101001011222
41221112000122310211
53323123144201013
6123544000510125
711113010662454
oct1512600326445
9353858331158
10113112100133
1143a74916a9a
1219b0901b345
13a8881a0686
14569064ab9b
152e20431508
hex1a5601ad25

113112100133 has 8 divisors (see below), whose sum is σ = 119778579648. Its totient is φ = 106447045824.

The previous prime is 113112100111. The next prime is 113112100139. The reversal of 113112100133 is 331001211311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113112100133 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113112100139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 190691 + ... + 512432.

It is an arithmetic number, because the mean of its divisors is an integer number (14972322456).

Almost surely, 2113112100133 is an apocalyptic number.

It is an amenable number.

113112100133 is a deficient number, since it is larger than the sum of its proper divisors (6666479515).

113112100133 is an equidigital number, since it uses as much as digits as its factorization.

113112100133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 712603.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113112100133 its reverse (331001211311), we get a palindrome (444113311444).

The spelling of 113112100133 in words is "one hundred thirteen billion, one hundred twelve million, one hundred thousand, one hundred thirty-three".

Divisors: 1 17 9463 160871 703123 11953091 6653652949 113112100133