113112100111 has 2 divisors, whose sum is σ = 113112100112. Its totient is φ = 113112100110.

The previous prime is 113112100093. The next prime is 113112100139. The reversal of 113112100111 is 111001211311.

It is a weak prime.

It is an emirp because it is prime and its reverse (111001211311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113112100111 - 2¹³ = 113112091919 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113112100091 and 113112100100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113112190111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556050055 + 56556050056.

It is an arithmetic number, because the mean of its divisors is an integer number (56556050056).

Almost surely, 2^113112100111 is an apocalyptic number.

113112100111 is a deficient number, since it is larger than the sum of its proper divisors (1).

113112100111 is an equidigital number, since it uses as much as digits as its factorization.

113112100111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 113112100111 its reverse (111001211311), we get a palindrome (224113311422).

The spelling of 113112100111 in words is "one hundred thirteen billion, one hundred twelve million, one hundred thousand, one hundred eleven".