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1131122002130 = 25293900420697
BaseRepresentation
bin10000011101011100001…
…000000000100011010010
311000010121211121021200022
4100131130020000203102
5122013014213032010
62223344050023442
7144502154244431
oct20353410004322
94003554537608
101131122002130
113a678497790a
12163276577b82
1382883755853
143ca6493b118
151e652d59d55
hex1075c2008d2

1131122002130 has 16 divisors (see below), whose sum is σ = 2106227176920. Its totient is φ = 436847117952.

The previous prime is 1131122002111. The next prime is 1131122002141. The reversal of 1131122002130 is 312002211311.

It can be written as a sum of positive squares in 4 ways, for example, as 605045955409 + 526076046721 = 777847^2 + 725311^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1131122002099 and 1131122002108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1950210059 + ... + 1950210638.

Almost surely, 21131122002130 is an apocalyptic number.

1131122002130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131122002130 is a deficient number, since it is larger than the sum of its proper divisors (975105174790).

1131122002130 is a wasteful number, since it uses less digits than its factorization.

1131122002130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3900420733.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1131122002130 its reverse (312002211311), we get a palindrome (1443124213441).

The spelling of 1131122002130 in words is "one trillion, one hundred thirty-one billion, one hundred twenty-two million, two thousand, one hundred thirty".

Divisors: 1 2 5 10 29 58 145 290 3900420697 7800841394 19502103485 39004206970 113112200213 226224400426 565561001065 1131122002130