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113113010133 = 3283263575753
BaseRepresentation
bin110100101011000001…
…1111000111111010101
3101210222001002021110200
41221112003320333111
53323123412311013
6123544032211113
711113021502514
oct1512603707725
9353861067420
10113113010133
1143a75388762
1219b09399a99
13a88842b936
14569080667b
152e20560e73
hex1a560f8fd5

113113010133 has 24 divisors (see below), whose sum is σ = 165982969152. Its totient is φ = 74216735808.

The previous prime is 113113010107. The next prime is 113113010141. The reversal of 113113010133 is 331010311311.

It is not a de Polignac number, because 113113010133 - 26 = 113113010069 is a prime.

It is a super-2 number, since 2×1131130101332 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113113015133) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 91416 + ... + 484337.

It is an arithmetic number, because the mean of its divisors is an integer number (6915957048).

Almost surely, 2113113010133 is an apocalyptic number.

It is an amenable number.

113113010133 is a deficient number, since it is larger than the sum of its proper divisors (52869959019).

113113010133 is a wasteful number, since it uses less digits than its factorization.

113113010133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 576105 (or 576102 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 113113010133 its reverse (331010311311), we get a palindrome (444123321444).

The spelling of 113113010133 in words is "one hundred thirteen billion, one hundred thirteen million, ten thousand, one hundred thirty-three".

Divisors: 1 3 9 83 249 263 747 789 2367 21829 65487 196461 575753 1727259 5181777 47787499 143362497 151423039 430087491 454269117 1362807351 12568112237 37704336711 113113010133