Base | Representation |
---|---|
bin | 1010010010011001111000… |
… | …0101100000001011010100 |
3 | 1111001100110000122202010110 |
4 | 2210212132011200023110 |
5 | 2440311021042224022 |
6 | 40020201235123020 |
7 | 2245133405150436 |
oct | 244463605401324 |
9 | 44040400582113 |
10 | 11311301133012 |
11 | 3671106671761 |
12 | 1328257a43470 |
13 | 6408606839ca |
14 | 2b1681574656 |
15 | 14937608c00c |
hex | a499e1602d4 |
11311301133012 has 48 divisors (see below), whose sum is σ = 26493259514624. Its totient is φ = 3756119040000.
The previous prime is 11311301132987. The next prime is 11311301133019. The reversal of 11311301133012 is 21033110311311.
It is a self number, because there is not a number n which added to its sum of digits gives 11311301133012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11311301133019) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31041312 + ... + 31403592.
Almost surely, 211311301133012 is an apocalyptic number.
11311301133012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11311301133012 is an abundant number, since it is smaller than the sum of its proper divisors (15181958381612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311301133012 is a wasteful number, since it uses less digits than its factorization.
11311301133012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 372160 (or 372158 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 11311301133012 its reverse (21033110311311), we get a palindrome (32344411444323).
The spelling of 11311301133012 in words is "eleven trillion, three hundred eleven billion, three hundred one million, one hundred thirty-three thousand, twelve".
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