Base | Representation |
---|---|
bin | 10000011101011100101… |
… | …000010001101111001100 |
3 | 11000010122102112001020200 |
4 | 100131130220101233030 |
5 | 122013023344224012 |
6 | 2223344551213500 |
7 | 144502316165310 |
oct | 20353450215714 |
9 | 4003572461220 |
10 | 1131130461132 |
11 | 3a6789725221 |
12 | 163279377290 |
13 | 82885427b89 |
14 | 3ca65addb40 |
15 | 1e65397b3dc |
hex | 1075ca11bcc |
1131130461132 has 288 divisors, whose sum is σ = 3392974061568. Its totient is φ = 311038054272.
The previous prime is 1131130461127. The next prime is 1131130461157. The reversal of 1131130461132 is 2311640311311.
1131130461132 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 13 + 0 + 4 + 611 + 32 = 666.
It is a super-2 number, since 2×11311304611322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131130461096 and 1131130461105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 703876273 + ... + 703877879.
It is an arithmetic number, because the mean of its divisors is an integer number (11781159936).
Almost surely, 21131130461132 is an apocalyptic number.
1131130461132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1131130461132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1696487030784).
1131130461132 is an abundant number, since it is smaller than the sum of its proper divisors (2261843600436).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131130461132 is a wasteful number, since it uses less digits than its factorization.
1131130461132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2625 (or 2620 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 27.
Adding to 1131130461132 its reverse (2311640311311), we get a palindrome (3442770772443).
The spelling of 1131130461132 in words is "one trillion, one hundred thirty-one billion, one hundred thirty million, four hundred sixty-one thousand, one hundred thirty-two".
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