113113131210000 has 250 divisors, whose sum is σ = 409096823160102. Its totient is φ = 30163501440000.

The previous prime is 113113131209917. The next prime is 113113131210017. The reversal of 113113131210000 is 12131311311.

113113131210000 is a `hidden beast` number, since 1 + 1 + 311 + 31 + 312 + 10 + 0 + 0 + 0 = 666.

It can be written as a sum of positive squares in 5 ways, for example, as 21142192548096 + 91970938661904 = 4598064^2 + 9590148^2 .

It is a tau number, because it is divible by the number of its divisors (250).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 49 ways as a sum of consecutive naturals, for example, 69012921 + ... + 70632920.

Almost surely, 2^{113113131210000} is an apocalyptic number.

113113131210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113113131210000 is an abundant number, since it is smaller than the sum of its proper divisors (295983691950102).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113113131210000 is an equidigital number, since it uses as much as digits as its factorization.

113113131210000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139645881 (or 139645851 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 113113131210000 its reverse (12131311311), we get a palindrome (113125262521311).

The spelling of 113113131210000 in words is "one hundred thirteen trillion, one hundred thirteen billion, one hundred thirty-one million, two hundred ten thousand".