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113113202400 = 253252111428197
BaseRepresentation
bin110100101011000010…
…0100111111011100000
3101210222001110001012200
41221112010213323200
53323123434434100
6123544040253200
711113023233202
oct1512604477340
9353861401180
10113113202400
1143a754aa160
1219b09471200
13a8884982c3
145690856772
152e2059ce00
hex1a56127ee0

113113202400 has 216 divisors, whose sum is σ = 435126228264. Its totient is φ = 27421363200.

The previous prime is 113113202351. The next prime is 113113202437. The reversal of 113113202400 is 4202311311.

113113202400 is a `hidden beast` number, since 1 + 131 + 132 + 0 + 2 + 400 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 634899 + ... + 793298.

It is an arithmetic number, because the mean of its divisors is an integer number (2014473279).

Almost surely, 2113113202400 is an apocalyptic number.

113113202400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113113202400 is an abundant number, since it is smaller than the sum of its proper divisors (322013025864).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113113202400 is a wasteful number, since it uses less digits than its factorization.

113113202400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1428234 (or 1428218 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 113113202400 its reverse (4202311311), we get a palindrome (117315513711).

It can be divided in two parts, 113113 and 202400, that added together give a palindrome (315513).

The spelling of 113113202400 in words is "one hundred thirteen billion, one hundred thirteen million, two hundred two thousand, four hundred".