Base | Representation |
---|---|
bin | 1010010010011010001111… |
… | …1111011101101000010011 |
3 | 1111001100200221002112100001 |
4 | 2210212203333131220103 |
5 | 2440311221423304021 |
6 | 40020215134510431 |
7 | 2245136020261423 |
oct | 244464377355023 |
9 | 44040627075301 |
10 | 11311400213011 |
11 | 3671157594a58 |
12 | 1328285065417 |
13 | 640878064822 |
14 | 2b16907a6483 |
15 | 14937eb0e091 |
hex | a49a3fdda13 |
11311400213011 has 2 divisors, whose sum is σ = 11311400213012. Its totient is φ = 11311400213010.
The previous prime is 11311400212963. The next prime is 11311400213041. The reversal of 11311400213011 is 11031200411311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311400213011 - 29 = 11311400212499 is a prime.
It is a super-2 number, since 2×113114002130112 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11311400213011.
It is not a weakly prime, because it can be changed into another prime (11311400213041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655700106505 + 5655700106506.
It is an arithmetic number, because the mean of its divisors is an integer number (5655700106506).
Almost surely, 211311400213011 is an apocalyptic number.
11311400213011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311400213011 is an equidigital number, since it uses as much as digits as its factorization.
11311400213011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 11311400213011 its reverse (11031200411311), we get a palindrome (22342600624322).
The spelling of 11311400213011 in words is "eleven trillion, three hundred eleven billion, four hundred million, two hundred thirteen thousand, eleven".
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