| Base | Representation |
|---|---|
| bin | 1010010010011010001111… |
| … | …1111011101101000110000 |
| 3 | 1111001100200221002112101010 |
| 4 | 2210212203333131220300 |
| 5 | 2440311221423304130 |
| 6 | 40020215134510520 |
| 7 | 2245136020261464 |
| oct | 244464377355060 |
| 9 | 44040627075333 |
| 10 | 11311400213040 |
| 11 | 3671157594a84 |
| 12 | 1328285065440 |
| 13 | 640878064845 |
| 14 | 2b16907a64a4 |
| 15 | 14937eb0e0b0 |
| hex | a49a3fdda30 |
11311400213040 has 320 divisors, whose sum is σ = 38352579563520. Its totient is φ = 2745433128960.
The previous prime is 11311400213011. The next prime is 11311400213041. The reversal of 11311400213040 is 4031200411311.
It is a super-2 number, since 2×113114002130402 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11311400212998 and 11311400213016.
It is not an unprimeable number, because it can be changed into a prime (11311400213041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 184503672 + ... + 184564968.
It is an arithmetic number, because the mean of its divisors is an integer number (119851811136).
Almost surely, 211311400213040 is an apocalyptic number.
11311400213040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11311400213040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19176289781760).
11311400213040 is an abundant number, since it is smaller than the sum of its proper divisors (27041179350480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311400213040 is a wasteful number, since it uses less digits than its factorization.
11311400213040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62820 (or 62814 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 11311400213040 its reverse (4031200411311), we get a palindrome (15342600624351).
The spelling of 11311400213040 in words is "eleven trillion, three hundred eleven billion, four hundred million, two hundred thirteen thousand, forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •