Base | Representation |
---|---|
bin | 10101000100011011… |
… | …01001001110101010 |
3 | 1002012022102200121201 |
4 | 22202031221032222 |
5 | 141131210422310 |
6 | 5110230554414 |
7 | 550210325560 |
oct | 124215511652 |
9 | 32168380551 |
10 | 11311420330 |
11 | 4885002571 |
12 | 2238208a0a |
13 | 10b35c3632 |
14 | 7943b7a30 |
15 | 4630a6e3a |
hex | 2a23693aa |
11311420330 has 16 divisors (see below), whose sum is σ = 23269207680. Its totient is φ = 3878201232.
The previous prime is 11311420321. The next prime is 11311420343. The reversal of 11311420330 is 3302411311.
It is a junction number, because it is equal to n+sod(n) for n = 11311420298 and 11311420307.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80795790 + ... + 80795929.
It is an arithmetic number, because the mean of its divisors is an integer number (1454325480).
Almost surely, 211311420330 is an apocalyptic number.
11311420330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11311420330 is an abundant number, since it is smaller than the sum of its proper divisors (11957787350).
11311420330 is a wasteful number, since it uses less digits than its factorization.
11311420330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161591733.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11311420330 its reverse (3302411311), we get a palindrome (14613831641).
The spelling of 11311420330 in words is "eleven billion, three hundred eleven million, four hundred twenty thousand, three hundred thirty".
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