Base | Representation |
---|---|
bin | 110100101011000100… |
… | …0011100010010110001 |
3 | 101210222010022220012112 |
4 | 1221112020130102301 |
5 | 3323124214001223 |
6 | 123544113535105 |
7 | 11113034602256 |
oct | 1512610342261 |
9 | 353863286175 |
10 | 113114203313 |
11 | 43a76023161 |
12 | 19b09874495 |
13 | a888758a67 |
14 | 5690a3742d |
15 | 2e206e9778 |
hex | 1a5621c4b1 |
113114203313 has 2 divisors, whose sum is σ = 113114203314. Its totient is φ = 113114203312.
The previous prime is 113114203291. The next prime is 113114203351. The reversal of 113114203313 is 313302411311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72236237824 + 40877965489 = 268768^2 + 202183^2 .
It is a cyclic number.
It is not a de Polignac number, because 113114203313 - 218 = 113113941169 is a prime.
It is a super-2 number, since 2×1131142033132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113114203393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56557101656 + 56557101657.
It is an arithmetic number, because the mean of its divisors is an integer number (56557101657).
Almost surely, 2113114203313 is an apocalyptic number.
It is an amenable number.
113114203313 is a deficient number, since it is larger than the sum of its proper divisors (1).
113114203313 is an equidigital number, since it uses as much as digits as its factorization.
113114203313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 113114203313 its reverse (313302411311), we get a palindrome (426416614624).
The spelling of 113114203313 in words is "one hundred thirteen billion, one hundred fourteen million, two hundred three thousand, three hundred thirteen".
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