Base | Representation |
---|---|
bin | 1010010010011010011000… |
… | …0101111001001111100110 |
3 | 1111001100210101101221002011 |
4 | 2210212212011321033212 |
5 | 2440311304434002124 |
6 | 40020222434104434 |
7 | 2245136625644215 |
oct | 244464605711746 |
9 | 44040711357064 |
10 | 11311435453414 |
11 | 3671175474658 |
12 | 1328294a1b11a |
13 | 640882452b35 |
14 | 2b169533b07c |
15 | 149382c70994 |
hex | a49a61793e6 |
11311435453414 has 4 divisors (see below), whose sum is σ = 16967153180124. Its totient is φ = 5655717726706.
The previous prime is 11311435453403. The next prime is 11311435453427. The reversal of 11311435453414 is 41435453411311.
11311435453414 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2827858863352 + ... + 2827858863355.
It is an arithmetic number, because the mean of its divisors is an integer number (4241788295031).
Almost surely, 211311435453414 is an apocalyptic number.
11311435453414 is a deficient number, since it is larger than the sum of its proper divisors (5655717726710).
11311435453414 is an equidigital number, since it uses as much as digits as its factorization.
11311435453414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5655717726709.
The product of its digits is 172800, while the sum is 40.
Adding to 11311435453414 its reverse (41435453411311), we get a palindrome (52746888864725).
The spelling of 11311435453414 in words is "eleven trillion, three hundred eleven billion, four hundred thirty-five million, four hundred fifty-three thousand, four hundred fourteen".
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