Base | Representation |
---|---|
bin | 1010010010011010011100… |
… | …0101010000110001100011 |
3 | 1111001100211112122212201011 |
4 | 2210212213011100301203 |
5 | 2440311323212033432 |
6 | 40020224230121351 |
7 | 2245140220101133 |
oct | 244464705206143 |
9 | 44040745585634 |
10 | 11311452064867 |
11 | 3671183890029 |
12 | 132829a4b0257 |
13 | 640885a1aab6 |
14 | 2b1697622ac3 |
15 | 149384452847 |
hex | a49a7150c63 |
11311452064867 has 2 divisors, whose sum is σ = 11311452064868. Its totient is φ = 11311452064866.
The previous prime is 11311452064823. The next prime is 11311452064909. The reversal of 11311452064867 is 76846025411311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311452064867 - 215 = 11311452032099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11311452064867.
It is not a weakly prime, because it can be changed into another prime (11311452064067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655726032433 + 5655726032434.
It is an arithmetic number, because the mean of its divisors is an integer number (5655726032434).
Almost surely, 211311452064867 is an apocalyptic number.
11311452064867 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311452064867 is an equidigital number, since it uses as much as digits as its factorization.
11311452064867 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 967680, while the sum is 49.
The spelling of 11311452064867 in words is "eleven trillion, three hundred eleven billion, four hundred fifty-two million, sixty-four thousand, eight hundred sixty-seven".
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