1131200130023 has 4 divisors (see below), whose sum is σ = 1197741314160. Its totient is φ = 1064658945888.

The previous prime is 1131200130017. The next prime is 1131200130059. The reversal of 1131200130023 is 3200310021311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131200130023 - 2¹⁴ = 1131200113639 is a prime.

It is a super-2 number, since 2×1131200130023² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 66541184119 = 1131200130023 / (1 + 1 + 3 + 1 + 2 + 0 + 0 + 1 + 3 + 0 + 0 + 2 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131200129983 and 1131200130010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131200130083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33270592043 + ... + 33270592076.

It is an arithmetic number, because the mean of its divisors is an integer number (299435328540).

Almost surely, 2^{1131200130023} is an apocalyptic number.

1131200130023 is a deficient number, since it is larger than the sum of its proper divisors (66541184137).

1131200130023 is an equidigital number, since it uses as much as digits as its factorization.

1131200130023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66541184136.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1131200130023 its reverse (3200310021311), we get a palindrome (4331510151334).

The spelling of 1131200130023 in words is "one trillion, one hundred thirty-one billion, two hundred million, one hundred thirty thousand, twenty-three".