1131200140221 has 12 divisors (see below), whose sum is σ = 1635003857760. Its totient is φ = 753649688520.

The previous prime is 1131200140201. The next prime is 1131200140229. The reversal of 1131200140221 is 1220410021311.

1131200140221 is a `hidden beast` number, since 11 + 31 + 200 + 1 + 402 + 21 = 666.

It is not a de Polignac number, because 1131200140221 - 2⁷ = 1131200140093 is a prime.

It is a super-3 number, since 3×1131200140221³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1131200140194 and 1131200140203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131200140229) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 40296715 + ... + 40324776.

It is an arithmetic number, because the mean of its divisors is an integer number (136250321480).

Almost surely, 2^{1131200140221} is an apocalyptic number.

It is an amenable number.

1131200140221 is a deficient number, since it is larger than the sum of its proper divisors (503803717539).

1131200140221 is a wasteful number, since it uses less digits than its factorization.

1131200140221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80623056 (or 80623053 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 1131200140221 its reverse (1220410021311), we get a palindrome (2351610161532).

The spelling of 1131200140221 in words is "one trillion, one hundred thirty-one billion, two hundred million, one hundred forty thousand, two hundred twenty-one".