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11312013113 = 19956844287
BaseRepresentation
bin10101000100011111…
…11001111100111001
31002012100112210202122
422202033321330321
5141131333404423
65110251411025
7550215345032
oct124217717471
932170483678
1011312013113
114885377975
122238453a75
1310b37703ab
147944cda89
154631728c8
hex2a23f9f39

11312013113 has 4 divisors (see below), whose sum is σ = 11368857600. Its totient is φ = 11255168628.

The previous prime is 11312013101. The next prime is 11312013169. The reversal of 11312013113 is 31131021311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11312013113 - 26 = 11312013049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312013091 and 11312013100.

It is not an unprimeable number, because it can be changed into a prime (11312013173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28421945 + ... + 28422342.

It is an arithmetic number, because the mean of its divisors is an integer number (2842214400).

Almost surely, 211312013113 is an apocalyptic number.

It is an amenable number.

11312013113 is a deficient number, since it is larger than the sum of its proper divisors (56844487).

11312013113 is an equidigital number, since it uses as much as digits as its factorization.

11312013113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56844486.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11312013113 its reverse (31131021311), we get a palindrome (42443034424).

The spelling of 11312013113 in words is "eleven billion, three hundred twelve million, thirteen thousand, one hundred thirteen".

Divisors: 1 199 56844287 11312013113