Base | Representation |
---|---|
bin | 10101000100011111… |
… | …11001111011111001 |
3 | 1002012100112210200021 |
4 | 22202033321323321 |
5 | 141131333404144 |
6 | 5110251410441 |
7 | 550215344611 |
oct | 124217717371 |
9 | 32170483607 |
10 | 11312013049 |
11 | 4885377917 |
12 | 2238453a21 |
13 | 10b377035c |
14 | 7944cda41 |
15 | 463172884 |
hex | 2a23f9ef9 |
11312013049 has 2 divisors, whose sum is σ = 11312013050. Its totient is φ = 11312013048.
The previous prime is 11312013047. The next prime is 11312013079. The reversal of 11312013049 is 94031021311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11073773824 + 238239225 = 105232^2 + 15435^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312013049 - 21 = 11312013047 is a prime.
Together with 11312013047, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11312013043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656006524 + 5656006525.
It is an arithmetic number, because the mean of its divisors is an integer number (5656006525).
Almost surely, 211312013049 is an apocalyptic number.
It is an amenable number.
11312013049 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312013049 is an equidigital number, since it uses as much as digits as its factorization.
11312013049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 11312013049 in words is "eleven billion, three hundred twelve million, thirteen thousand, forty-nine".
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