11312100141 has 4 divisors (see below), whose sum is σ = 15082800192. Its totient is φ = 7541400092.

The previous prime is 11312100131. The next prime is 11312100179. The reversal of 11312100141 is 14100121311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11312100141 - 2¹¹ = 11312098093 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11312100141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312100131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885350021 + ... + 1885350026.

It is an arithmetic number, because the mean of its divisors is an integer number (3770700048).

Almost surely, 2^11312100141 is an apocalyptic number.

It is an amenable number.

11312100141 is a deficient number, since it is larger than the sum of its proper divisors (3770700051).

11312100141 is an equidigital number, since it uses as much as digits as its factorization.

11312100141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3770700050.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11312100141 its reverse (14100121311), we get a palindrome (25412221452).

The spelling of 11312100141 in words is "eleven billion, three hundred twelve million, one hundred thousand, one hundred forty-one".