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1131210020220 = 2235727910944683
BaseRepresentation
bin10000011101100001010…
…111110001010101111100
311000010211222020001210120
4100131201113301111330
5122013204231121340
62223400512334540
7144504303344100
oct20354127612574
94003758201716
101131210020220
113a681a625135
1216329bb44450
1382898a62667
143ca724cd900
151e65a9444d0
hex107615f157c

1131210020220 has 288 divisors, whose sum is σ = 3765467059200. Its totient is φ = 252941584896.

The previous prime is 1131210020191. The next prime is 1131210020243. The reversal of 1131210020220 is 220200121311.

It is a super-2 number, since 2×11312100202202 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1131210020220.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 25293999 + ... + 25338681.

It is an arithmetic number, because the mean of its divisors is an integer number (13074538400).

Almost surely, 21131210020220 is an apocalyptic number.

1131210020220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131210020220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1882733529600).

1131210020220 is an abundant number, since it is smaller than the sum of its proper divisors (2634257038980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131210020220 is a wasteful number, since it uses less digits than its factorization.

1131210020220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44897 (or 44888 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1131210020220 its reverse (220200121311), we get a palindrome (1351410141531).

The spelling of 1131210020220 in words is "one trillion, one hundred thirty-one billion, two hundred ten million, twenty thousand, two hundred twenty".