Base | Representation |
---|---|
bin | 1010010010011100111001… |
… | …0111010010100000111110 |
3 | 1111001102112110202102201101 |
4 | 2210213032113102200332 |
5 | 2440314200420231024 |
6 | 40020413451403314 |
7 | 2245162441604212 |
oct | 244471627224076 |
9 | 44042473672641 |
10 | 11312111102014 |
11 | 36714918a1428 |
12 | 132844315353a |
13 | 64095c4172c8 |
14 | 2b171ad76942 |
15 | 1493c2232c44 |
hex | a49ce5d283e |
11312111102014 has 16 divisors (see below), whose sum is σ = 17012068875360. Its totient is φ = 5641421960160.
The previous prime is 11312111102011. The next prime is 11312111102027. The reversal of 11312111102014 is 41020111121311.
11312111102014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11312111101982 and 11312111102000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312111102011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 91361692 + ... + 91485424.
It is an arithmetic number, because the mean of its divisors is an integer number (1063254304710).
Almost surely, 211312111102014 is an apocalyptic number.
11312111102014 is a deficient number, since it is larger than the sum of its proper divisors (5699957773346).
11312111102014 is a wasteful number, since it uses less digits than its factorization.
11312111102014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241635.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 11312111102014 its reverse (41020111121311), we get a palindrome (52332222223325).
The spelling of 11312111102014 in words is "eleven trillion, three hundred twelve billion, one hundred eleven million, one hundred two thousand, fourteen".
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