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11312111102014 = 2389117511123733
BaseRepresentation
bin1010010010011100111001…
…0111010010100000111110
31111001102112110202102201101
42210213032113102200332
52440314200420231024
640020413451403314
72245162441604212
oct244471627224076
944042473672641
1011312111102014
1136714918a1428
12132844315353a
1364095c4172c8
142b171ad76942
151493c2232c44
hexa49ce5d283e

11312111102014 has 16 divisors (see below), whose sum is σ = 17012068875360. Its totient is φ = 5641421960160.

The previous prime is 11312111102011. The next prime is 11312111102027. The reversal of 11312111102014 is 41020111121311.

11312111102014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11312111101982 and 11312111102000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312111102011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 91361692 + ... + 91485424.

It is an arithmetic number, because the mean of its divisors is an integer number (1063254304710).

Almost surely, 211312111102014 is an apocalyptic number.

11312111102014 is a deficient number, since it is larger than the sum of its proper divisors (5699957773346).

11312111102014 is a wasteful number, since it uses less digits than its factorization.

11312111102014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 241635.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 11312111102014 its reverse (41020111121311), we get a palindrome (52332222223325).

The spelling of 11312111102014 in words is "eleven trillion, three hundred twelve billion, one hundred eleven million, one hundred two thousand, fourteen".

Divisors: 1 2 389 778 117511 123733 235022 247466 45711779 48132137 91423558 96264274 14539988563 29079977126 5656055551007 11312111102014