Base | Representation |
---|---|
bin | 1010010010011100111001… |
… | …0111010010100001011001 |
3 | 1111001102112110202102202101 |
4 | 2210213032113102201121 |
5 | 2440314200420231131 |
6 | 40020413451403401 |
7 | 2245162441604251 |
oct | 244471627224131 |
9 | 44042473672671 |
10 | 11312111102041 |
11 | 36714918a1452 |
12 | 1328443153561 |
13 | 64095c417319 |
14 | 2b171ad76961 |
15 | 1493c2232c61 |
hex | a49ce5d2859 |
11312111102041 has 2 divisors, whose sum is σ = 11312111102042. Its totient is φ = 11312111102040.
The previous prime is 11312111102029. The next prime is 11312111102101. The reversal of 11312111102041 is 14020111121311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11086262796816 + 225848305225 = 3329604^2 + 475235^2 .
It is an emirp because it is prime and its reverse (14020111121311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11312111102041 - 229 = 11311574231129 is a prime.
It is not a weakly prime, because it can be changed into another prime (11312111102011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656055551020 + 5656055551021.
It is an arithmetic number, because the mean of its divisors is an integer number (5656055551021).
Almost surely, 211312111102041 is an apocalyptic number.
It is an amenable number.
11312111102041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312111102041 is an equidigital number, since it uses as much as digits as its factorization.
11312111102041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 11312111102041 its reverse (14020111121311), we get a palindrome (25332222223352).
The spelling of 11312111102041 in words is "eleven trillion, three hundred twelve billion, one hundred eleven million, one hundred two thousand, forty-one".
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