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113121113031 = 342719151361
BaseRepresentation
bin110100101011010001…
…0110011001111000111
3101210222121022221120000
41221112202303033013
53323133001104111
6123544522012343
711113150411233
oct1512642631707
9353877287500
10113121113031
1143a79a12573
1219b100470b3
13a88a007b54
1456919155c3
152e21111c56
hex1a568b33c7

113121113031 has 20 divisors (see below), whose sum is σ = 168992895984. Its totient is φ = 75409833600.

The previous prime is 113121112981. The next prime is 113121113033. The reversal of 113121113031 is 130311121311.

It is not a de Polignac number, because 113121113031 - 29 = 113121112519 is a prime.

It is a super-2 number, since 2×1131211130312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113121112995 and 113121113013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113121113033) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 2176791 + ... + 2228151.

Almost surely, 2113121113031 is an apocalyptic number.

113121113031 is a deficient number, since it is larger than the sum of its proper divisors (55871782953).

113121113031 is an equidigital number, since it uses as much as digits as its factorization.

113121113031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78564 (or 78555 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 113121113031 its reverse (130311121311), we get a palindrome (243432234342).

The spelling of 113121113031 in words is "one hundred thirteen billion, one hundred twenty-one million, one hundred thirteen thousand, thirty-one".

Divisors: 1 3 9 27 81 27191 51361 81573 154083 244719 462249 734157 1386747 2202471 4160241 1396556951 4189670853 12569012559 37707037677 113121113031