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113121113033 is a prime number
BaseRepresentation
bin110100101011010001…
…0110011001111001001
3101210222121022221120002
41221112202303033021
53323133001104113
6123544522012345
711113150411235
oct1512642631711
9353877287502
10113121113033
1143a79a12575
1219b100470b5
13a88a007b56
1456919155c5
152e21111c58
hex1a568b33c9

113121113033 has 2 divisors, whose sum is σ = 113121113034. Its totient is φ = 113121113032.

The previous prime is 113121112981. The next prime is 113121113041. The reversal of 113121113033 is 330311121311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106467121849 + 6653991184 = 326293^2 + 81572^2 .

It is a cyclic number.

It is not a de Polignac number, because 113121113033 - 28 = 113121112777 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113121112996 and 113121113014.

It is not a weakly prime, because it can be changed into another prime (113121113933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560556516 + 56560556517.

It is an arithmetic number, because the mean of its divisors is an integer number (56560556517).

Almost surely, 2113121113033 is an apocalyptic number.

It is an amenable number.

113121113033 is a deficient number, since it is larger than the sum of its proper divisors (1).

113121113033 is an equidigital number, since it uses as much as digits as its factorization.

113121113033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113121113033 its reverse (330311121311), we get a palindrome (443432234344).

The spelling of 113121113033 in words is "one hundred thirteen billion, one hundred twenty-one million, one hundred thirteen thousand, thirty-three".