Base | Representation |
---|---|
bin | 110100101011010001… |
… | …0111000011011101010 |
3 | 101210222121101000202021 |
4 | 1221112202320123222 |
5 | 3323133002244224 |
6 | 123544522255054 |
7 | 11113150530256 |
oct | 1512642703352 |
9 | 353877330667 |
10 | 113121134314 |
11 | 43a79a27561 |
12 | 19b1005748a |
13 | a88a014746 |
14 | 569191d266 |
15 | 2e211181e4 |
hex | 1a568b86ea |
113121134314 has 4 divisors (see below), whose sum is σ = 169681701474. Its totient is φ = 56560567156.
The previous prime is 113121134281. The next prime is 113121134327. The reversal of 113121134314 is 413431121311.
113121134314 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 413431121311 = 13 ⋅31802393947.
It can be written as a sum of positive squares in only one way, i.e., 110619434025 + 2501700289 = 332595^2 + 50017^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28280283577 + ... + 28280283580.
Almost surely, 2113121134314 is an apocalyptic number.
113121134314 is a deficient number, since it is larger than the sum of its proper divisors (56560567160).
113121134314 is an equidigital number, since it uses as much as digits as its factorization.
113121134314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56560567159.
The product of its digits is 864, while the sum is 25.
Adding to 113121134314 its reverse (413431121311), we get a palindrome (526552255625).
The spelling of 113121134314 in words is "one hundred thirteen billion, one hundred twenty-one million, one hundred thirty-four thousand, three hundred fourteen".
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