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1131212153 is a prime number
BaseRepresentation
bin100001101101100…
…1110110101111001
32220211120112100102
41003123032311321
54304042242103
6304125445145
740014100421
oct10333166571
92824515312
101131212153
115305a3485
12276a107b5
1315048b606
14aa345481
156949de88
hex436ced79

1131212153 has 2 divisors, whose sum is σ = 1131212154. Its totient is φ = 1131212152.

The previous prime is 1131212141. The next prime is 1131212189. The reversal of 1131212153 is 3512121311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1102771264 + 28440889 = 33208^2 + 5333^2 .

It is an emirp because it is prime and its reverse (3512121311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131212153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131212123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606076 + 565606077.

It is an arithmetic number, because the mean of its divisors is an integer number (565606077).

Almost surely, 21131212153 is an apocalyptic number.

It is an amenable number.

1131212153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131212153 is an equidigital number, since it uses as much as digits as its factorization.

1131212153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 180, while the sum is 20.

The square root of 1131212153 is about 33633.4974839073. The cubic root of 1131212153 is about 1041.9527392748.

Adding to 1131212153 its reverse (3512121311), we get a palindrome (4643333464).

The spelling of 1131212153 in words is "one billion, one hundred thirty-one million, two hundred twelve thousand, one hundred fifty-three".