113121310000003 has 2 divisors, whose sum is σ = 113121310000004. Its totient is φ = 113121310000002.

The previous prime is 113121309999959. The next prime is 113121310000009. The reversal of 113121310000003 is 300000013121311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113121310000003 is a prime.

It is a super-2 number, since 2×113121310000003² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113121310000009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560655000001 + 56560655000002.

It is an arithmetic number, because the mean of its divisors is an integer number (56560655000002).

Almost surely, 2^{113121310000003} is an apocalyptic number.

113121310000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

113121310000003 is an equidigital number, since it uses as much as digits as its factorization.

113121310000003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 113121310000003 its reverse (300000013121311), we get a palindrome (413121323121314).

The spelling of 113121310000003 in words is "one hundred thirteen trillion, one hundred twenty-one billion, three hundred ten million, three", and thus it is an aban number.