113121321132 has 12 divisors (see below), whose sum is σ = 263949749336. Its totient is φ = 37707107040.

The previous prime is 113121321127. The next prime is 113121321143. The reversal of 113121321132 is 231123121311.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×113121321132² (a number of 23 digits) contains 22 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 113121321099 and 113121321108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4713388369 + ... + 4713388392.

Almost surely, 2^113121321132 is an apocalyptic number.

113121321132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

113121321132 is an abundant number, since it is smaller than the sum of its proper divisors (150828428204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113121321132 is a wasteful number, since it uses less digits than its factorization.

113121321132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9426776768 (or 9426776766 counting only the distinct ones).

The product of its digits is 216, while the sum is 21.

Adding to 113121321132 its reverse (231123121311), we get a palindrome (344244442443).

The spelling of 113121321132 in words is "one hundred thirteen billion, one hundred twenty-one million, three hundred twenty-one thousand, one hundred thirty-two".