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1131213401 is a prime number
BaseRepresentation
bin100001101101100…
…1111001001011001
32220211120121001122
41003123033021121
54304042312101
6304125455025
740014104153
oct10333171131
92824517048
101131213401
115305a440a
12276a11475
1315048c056
14aa345ad3
156949e51b
hex436cf259

1131213401 has 2 divisors, whose sum is σ = 1131213402. Its totient is φ = 1131213400.

The previous prime is 1131213379. The next prime is 1131213409. The reversal of 1131213401 is 1043121311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 833823376 + 297390025 = 28876^2 + 17245^2 .

It is an emirp because it is prime and its reverse (1043121311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131213401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1131213401.

It is not a weakly prime, because it can be changed into another prime (1131213409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606700 + 565606701.

It is an arithmetic number, because the mean of its divisors is an integer number (565606701).

Almost surely, 21131213401 is an apocalyptic number.

It is an amenable number.

1131213401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131213401 is an equidigital number, since it uses as much as digits as its factorization.

1131213401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1131213401 is about 33633.5160368344. The cubic root of 1131213401 is about 1041.9531224498.

Adding to 1131213401 its reverse (1043121311), we get a palindrome (2174334712).

The spelling of 1131213401 in words is "one billion, one hundred thirty-one million, two hundred thirteen thousand, four hundred one".