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1131214121 is a prime number
BaseRepresentation
bin100001101101100…
…1111010100101001
32220211120122001022
41003123033110221
54304042322441
6304125502225
740014106232
oct10333172451
92824518038
101131214121
115305a4a04
12276a11975
1315048c48b
14aa346089
156949e84b
hex436cf529

1131214121 has 2 divisors, whose sum is σ = 1131214122. Its totient is φ = 1131214120.

The previous prime is 1131214111. The next prime is 1131214127. The reversal of 1131214121 is 1214121311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 975937600 + 155276521 = 31240^2 + 12461^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131214121 - 26 = 1131214057 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1131214121.

It is not a weakly prime, because it can be changed into another prime (1131214127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565607060 + 565607061.

It is an arithmetic number, because the mean of its divisors is an integer number (565607061).

Almost surely, 21131214121 is an apocalyptic number.

It is an amenable number.

1131214121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131214121 is an equidigital number, since it uses as much as digits as its factorization.

1131214121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 17.

The square root of 1131214121 is about 33633.5267404416. The cubic root of 1131214121 is about 1041.9533435121.

Adding to 1131214121 its reverse (1214121311), we get a palindrome (2345335432).

The spelling of 1131214121 in words is "one billion, one hundred thirty-one million, two hundred fourteen thousand, one hundred twenty-one".