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1131222300017 is a prime number
BaseRepresentation
bin10000011101100010000…
…110100111010101110001
311000010212211022221111212
4100131202012213111301
5122013220402100032
62223402031445505
7144504512620205
oct20354206472561
94003784287455
101131222300017
113a6826552127
121632a4086895
138289b471b04
143ca73da8b05
151e65ba6cbb2
hex107621a7571

1131222300017 has 2 divisors, whose sum is σ = 1131222300018. Its totient is φ = 1131222300016.

The previous prime is 1131222300001. The next prime is 1131222300037. The reversal of 1131222300017 is 7100032221311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1113607436176 + 17614863841 = 1055276^2 + 132721^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131222300017 - 24 = 1131222300001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131222299965 and 1131222300001.

It is not a weakly prime, because it can be changed into another prime (1131222300037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565611150008 + 565611150009.

It is an arithmetic number, because the mean of its divisors is an integer number (565611150009).

Almost surely, 21131222300017 is an apocalyptic number.

It is an amenable number.

1131222300017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131222300017 is an equidigital number, since it uses as much as digits as its factorization.

1131222300017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1131222300017 its reverse (7100032221311), we get a palindrome (8231254521328).

The spelling of 1131222300017 in words is "one trillion, one hundred thirty-one billion, two hundred twenty-two million, three hundred thousand, seventeen".