11312233031137 has 2 divisors, whose sum is σ = 11312233031138. Its totient is φ = 11312233031136.

The previous prime is 11312233031063. The next prime is 11312233031159. The reversal of 11312233031137 is 73113033221311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9132266417296 + 2179966613841 = 3021964^2 + 1476471^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312233031137 - 2¹⁵ = 11312232998369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312233031099 and 11312233031108.

It is not a weakly prime, because it can be changed into another prime (11312233031537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656116515568 + 5656116515569.

It is an arithmetic number, because the mean of its divisors is an integer number (5656116515569).

Almost surely, 2^{11312233031137} is an apocalyptic number.

It is an amenable number.

11312233031137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312233031137 is an equidigital number, since it uses as much as digits as its factorization.

11312233031137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 31.

Adding to 11312233031137 its reverse (73113033221311), we get a palindrome (84425266252448).

The spelling of 11312233031137 in words is "eleven trillion, three hundred twelve billion, two hundred thirty-three million, thirty-one thousand, one hundred thirty-seven".