1131224120223 has 12 divisors (see below), whose sum is σ = 1576728265560. Its totient is φ = 721360307536.

The previous prime is 1131224120183. The next prime is 1131224120233. The reversal of 1131224120223 is 3220214221311.

It is a de Polignac number, because none of the positive numbers 2^k-1131224120223 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131224120193 and 1131224120202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131224120233) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 356401728 + ... + 356404901.

It is an arithmetic number, because the mean of its divisors is an integer number (131394022130).

Almost surely, 2^{1131224120223} is an apocalyptic number.

1131224120223 is a deficient number, since it is larger than the sum of its proper divisors (445504145337).

1131224120223 is an equidigital number, since it uses as much as digits as its factorization.

1131224120223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 712806678 (or 712806655 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1131224120223 its reverse (3220214221311), we get a palindrome (4351438341534).

The spelling of 1131224120223 in words is "one trillion, one hundred thirty-one billion, two hundred twenty-four million, one hundred twenty thousand, two hundred twenty-three".