Base | Representation |
---|---|
bin | 1010010010011101011011… |
… | …1110001001000000111101 |
3 | 1111001102220112110211121120 |
4 | 2210213112332021000331 |
5 | 2440314444402120240 |
6 | 40020440050421153 |
7 | 2245166144161440 |
oct | 244472676110075 |
9 | 44042815424546 |
10 | 11312255504445 |
11 | 3671556360085 |
12 | 13284835917b9 |
13 | 64098330642c |
14 | 2b1732205657 |
15 | 1493cec58ad0 |
hex | a49d6f8903d |
11312255504445 has 32 divisors (see below), whose sum is σ = 21773965486080. Its totient is φ = 4899142232640.
The previous prime is 11312255504413. The next prime is 11312255504461. The reversal of 11312255504445 is 54440555221311.
11312255504445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11312255504445 - 25 = 11312255504413 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11312255504397 and 11312255504406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2835149761 + ... + 2835153750.
It is an arithmetic number, because the mean of its divisors is an integer number (680436421440).
Almost surely, 211312255504445 is an apocalyptic number.
11312255504445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11312255504445 is a deficient number, since it is larger than the sum of its proper divisors (10461709981635).
11312255504445 is a wasteful number, since it uses less digits than its factorization.
11312255504445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5670303545.
The product of its (nonzero) digits is 480000, while the sum is 42.
The spelling of 11312255504445 in words is "eleven trillion, three hundred twelve billion, two hundred fifty-five million, five hundred four thousand, four hundred forty-five".
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