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113123031120 = 243251141615711
BaseRepresentation
bin110100101011010101…
…0000111100001010000
3101210222201221101200100
41221112222013201100
53323133443443440
6123545031052400
711113202620311
oct1512652074120
9353881841610
10113123031120
1143a80002670
1219b10811100
13a88a529c08
145691c94608
152e21390230
hex1a56a87850

113123031120 has 480 divisors, whose sum is σ = 431585376768. Its totient is φ = 26311680000.

The previous prime is 113123031107. The next prime is 113123031121. The reversal of 113123031120 is 21130321311.

113123031120 is a `hidden beast` number, since 11 + 312 + 30 + 311 + 2 + 0 = 666.

113123031120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113123031093 and 113123031102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113123031121) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 19805065 + ... + 19810775.

Almost surely, 2113123031120 is an apocalyptic number.

113123031120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113123031120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215792688384).

113123031120 is an abundant number, since it is smaller than the sum of its proper divisors (318462345648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113123031120 is a wasteful number, since it uses less digits than its factorization.

113123031120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5843 (or 5834 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113123031120 its reverse (21130321311), we get a palindrome (134253352431).

Subtracting from 113123031120 its reverse (21130321311), we obtain a square (91992709809 = 3033032).

The spelling of 113123031120 in words is "one hundred thirteen billion, one hundred twenty-three million, thirty-one thousand, one hundred twenty".