Base | Representation |
---|---|
bin | 1010010010011101101001… |
… | …1010010010000001001001 |
3 | 1111001110001120001201212111 |
4 | 2210213122122102001021 |
5 | 2440320104140304001 |
6 | 40020445511342321 |
7 | 2245200444533113 |
oct | 244473232220111 |
9 | 44043046051774 |
10 | 11312313213001 |
11 | 36715859963a9 |
12 | 132849a9819a1 |
13 | 6409922603c8 |
14 | 2b1739b483b3 |
15 | 1493d4d57851 |
hex | a49da692049 |
11312313213001 has 2 divisors, whose sum is σ = 11312313213002. Its totient is φ = 11312313213000.
The previous prime is 11312313212951. The next prime is 11312313213053. The reversal of 11312313213001 is 10031231321311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10670832357376 + 641480855625 = 3266624^2 + 800925^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312313213001 - 29 = 11312313212489 is a prime.
It is not a weakly prime, because it can be changed into another prime (11312313213401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656156606500 + 5656156606501.
It is an arithmetic number, because the mean of its divisors is an integer number (5656156606501).
Almost surely, 211312313213001 is an apocalyptic number.
It is an amenable number.
11312313213001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312313213001 is an equidigital number, since it uses as much as digits as its factorization.
11312313213001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11312313213001 its reverse (10031231321311), we get a palindrome (21343544534312).
The spelling of 11312313213001 in words is "eleven trillion, three hundred twelve billion, three hundred thirteen million, two hundred thirteen thousand, one".
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