Base | Representation |
---|---|
bin | 1010010010011101101100… |
… | …0000000000001010010101 |
3 | 1111001110002020200010010000 |
4 | 2210213123000000022111 |
5 | 2440320114203220313 |
6 | 40020450503321513 |
7 | 2245200624556062 |
oct | 244473300001225 |
9 | 44043066603100 |
10 | 11312323101333 |
11 | 367159052a681 |
12 | 13284a2150299 |
13 | 6409943131a7 |
14 | 2b173b19dc69 |
15 | 1493d5b5c673 |
hex | a49db000295 |
11312323101333 has 10 divisors (see below), whose sum is σ = 16898655497174. Its totient is φ = 7541548734168.
The previous prime is 11312323101329. The next prime is 11312323101341. The reversal of 11312323101333 is 33310132321311.
11312323101333 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 2 + 323 + 1 + 0 + 1 + 333 = 666.
It can be written as a sum of positive squares in only one way, i.e., 10648722244644 + 663600856689 = 3263238^2 + 814617^2 .
It is not a de Polignac number, because 11312323101333 - 22 = 11312323101329 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11312323101297 and 11312323101306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312323101133) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 69829154866 + ... + 69829155027.
Almost surely, 211312323101333 is an apocalyptic number.
It is an amenable number.
11312323101333 is a deficient number, since it is larger than the sum of its proper divisors (5586332395841).
11312323101333 is an equidigital number, since it uses as much as digits as its factorization.
11312323101333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139658309905 (or 139658309896 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 27.
Adding to 11312323101333 its reverse (33310132321311), we get a palindrome (44622455422644).
The spelling of 11312323101333 in words is "eleven trillion, three hundred twelve billion, three hundred twenty-three million, one hundred one thousand, three hundred thirty-three".
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