Base | Representation |
---|---|
bin | 1010010010011101101101… |
… | …1010011100010010101111 |
3 | 1111001110002201201020121121 |
4 | 2210213123122130102233 |
5 | 2440320122442013203 |
6 | 40020451312041411 |
7 | 2245201040514016 |
oct | 244473332342257 |
9 | 44043081636547 |
10 | 11312330032303 |
11 | 3671594433a53 |
12 | 13284a4533267 |
13 | 64099589bb61 |
14 | 2b173c085a7d |
15 | 1493d657b0bd |
hex | a49db69c4af |
11312330032303 has 4 divisors (see below), whose sum is σ = 11312810266840. Its totient is φ = 11311849797768.
The previous prime is 11312330032291. The next prime is 11312330032321. The reversal of 11312330032303 is 30323003321311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11312330032303 - 217 = 11312329901231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312330632303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240081933 + ... + 240129046.
It is an arithmetic number, because the mean of its divisors is an integer number (2828202566710).
Almost surely, 211312330032303 is an apocalyptic number.
11312330032303 is a deficient number, since it is larger than the sum of its proper divisors (480234537).
11312330032303 is an equidigital number, since it uses as much as digits as its factorization.
11312330032303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 480234536.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 11312330032303 its reverse (30323003321311), we get a palindrome (41635333353614).
The spelling of 11312330032303 in words is "eleven trillion, three hundred twelve billion, three hundred thirty million, thirty-two thousand, three hundred three".
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