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113123340433 is a prime number
BaseRepresentation
bin110100101011010101…
…1010011000010010001
3101210222202112002222101
41221112223103002101
53323134033343213
6123545041440401
711113205346145
oct1512653230221
9353882462871
10113123340433
1143a801a3aa4
1219b10940101
13a88a60793c
145691d35225
152e21401bdd
hex1a56ad3091

113123340433 has 2 divisors, whose sum is σ = 113123340434. Its totient is φ = 113123340432.

The previous prime is 113123340377. The next prime is 113123340457. The reversal of 113123340433 is 334043321311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83020049424 + 30103291009 = 288132^2 + 173503^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113123340433 is a prime.

It is not a weakly prime, because it can be changed into another prime (113123343433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561670216 + 56561670217.

It is an arithmetic number, because the mean of its divisors is an integer number (56561670217).

Almost surely, 2113123340433 is an apocalyptic number.

It is an amenable number.

113123340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113123340433 is an equidigital number, since it uses as much as digits as its factorization.

113123340433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 113123340433 its reverse (334043321311), we get a palindrome (447166661744).

The spelling of 113123340433 in words is "one hundred thirteen billion, one hundred twenty-three million, three hundred forty thousand, four hundred thirty-three".