11312413133 has 4 divisors (see below), whose sum is σ = 12928472160. Its totient is φ = 9696354108.

The previous prime is 11312413117. The next prime is 11312413157. The reversal of 11312413133 is 33131421311.

11312413133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33131421311 = 139 ⋅238355549.

It is not a de Polignac number, because 11312413133 - 2⁴ = 11312413117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312413099 and 11312413108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312413733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808029503 + ... + 808029516.

It is an arithmetic number, because the mean of its divisors is an integer number (3232118040).

Almost surely, 2^11312413133 is an apocalyptic number.

It is an amenable number.

11312413133 is a deficient number, since it is larger than the sum of its proper divisors (1616059027).

11312413133 is an equidigital number, since it uses as much as digits as its factorization.

11312413133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1616059026.

The product of its digits is 648, while the sum is 23.

Adding to 11312413133 its reverse (33131421311), we get a palindrome (44443834444).

The spelling of 11312413133 in words is "eleven billion, three hundred twelve million, four hundred thirteen thousand, one hundred thirty-three".