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11312413157 is a prime number
BaseRepresentation
bin10101000100100010…
…11011100111100101
31002012101022010112002
422202101123213211
5141131434210112
65110304135045
7550221632243
oct124221334745
932171263462
1011312413157
114885620491
122238607485
1310b38804c6
14794595793
154632011c2
hex2a245b9e5

11312413157 has 2 divisors, whose sum is σ = 11312413158. Its totient is φ = 11312413156.

The previous prime is 11312413117. The next prime is 11312413213. The reversal of 11312413157 is 75131421311.

11312413157 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11293525441 + 18887716 = 106271^2 + 4346^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312413157 - 214 = 11312396773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312413117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656206578 + 5656206579.

It is an arithmetic number, because the mean of its divisors is an integer number (5656206579).

Almost surely, 211312413157 is an apocalyptic number.

It is an amenable number.

11312413157 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312413157 is an equidigital number, since it uses as much as digits as its factorization.

11312413157 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2520, while the sum is 29.

Adding to 11312413157 its reverse (75131421311), we get a palindrome (86443834468).

The spelling of 11312413157 in words is "eleven billion, three hundred twelve million, four hundred thirteen thousand, one hundred fifty-seven".