Base | Representation |
---|---|
bin | 11001101110001011000100… |
… | …010000111101001100110011 |
3 | 112211112120011220210200011001 |
4 | 121232023010100331030303 |
5 | 104311411220200440423 |
6 | 1040332302500502431 |
7 | 32553643452453052 |
oct | 3156130420751463 |
9 | 484476156720131 |
10 | 113124141421363 |
11 | 33054751768176 |
12 | 108302720aaa17 |
13 | 4b17739cc43b7 |
14 | 1dd13481c8399 |
15 | d129427b9cad |
hex | 66e2c443d333 |
113124141421363 has 2 divisors, whose sum is σ = 113124141421364. Its totient is φ = 113124141421362.
The previous prime is 113124141421253. The next prime is 113124141421381. The reversal of 113124141421363 is 363124141421311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113124141421363 is a prime.
It is not a weakly prime, because it can be changed into another prime (113124141424363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56562070710681 + 56562070710682.
It is an arithmetic number, because the mean of its divisors is an integer number (56562070710682).
Almost surely, 2113124141421363 is an apocalyptic number.
113124141421363 is a deficient number, since it is larger than the sum of its proper divisors (1).
113124141421363 is an equidigital number, since it uses as much as digits as its factorization.
113124141421363 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41472, while the sum is 37.
Adding to 113124141421363 its reverse (363124141421311), we get a palindrome (476248282842674).
The spelling of 113124141421363 in words is "one hundred thirteen trillion, one hundred twenty-four billion, one hundred forty-one million, four hundred twenty-one thousand, three hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.099 sec. • engine limits •