Base | Representation |
---|---|
bin | 1010010010011110000110… |
… | …0011010100010011001011 |
3 | 1111001110100220111200010120 |
4 | 2210213201203110103023 |
5 | 2440320330323202110 |
6 | 40020505431314323 |
7 | 2245203431100666 |
oct | 244474143242313 |
9 | 44043326450116 |
10 | 11312433022155 |
11 | 3671637587831 |
12 | 1328512b1b9a3 |
13 | 6409b101b4b5 |
14 | 2b174ba146dd |
15 | 1493e0621870 |
hex | a49e18d44cb |
11312433022155 has 32 divisors (see below), whose sum is σ = 18243408396288. Its totient is φ = 5985464284800.
The previous prime is 11312433022133. The next prime is 11312433022237. The reversal of 11312433022155 is 55122033421311.
It is a happy number.
It is not a de Polignac number, because 11312433022155 - 215 = 11312432989387 is a prime.
It is a super-2 number, since 2×113124330221552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36939765 + ... + 37244745.
It is an arithmetic number, because the mean of its divisors is an integer number (570106512384).
Almost surely, 211312433022155 is an apocalyptic number.
11312433022155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11312433022155 is a deficient number, since it is larger than the sum of its proper divisors (6930975374133).
11312433022155 is a wasteful number, since it uses less digits than its factorization.
11312433022155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 324587.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 11312433022155 its reverse (55122033421311), we get a palindrome (66434466443466).
The spelling of 11312433022155 in words is "eleven trillion, three hundred twelve billion, four hundred thirty-three million, twenty-two thousand, one hundred fifty-five".
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