11312435433 has 8 divisors (see below), whose sum is σ = 16243497088. Its totient is φ = 6961498704.

The previous prime is 11312435423. The next prime is 11312435471. The reversal of 11312435433 is 33453421311.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11312435433 - 2⁹ = 11312434921 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11312435433.

It is not an unprimeable number, because it can be changed into a prime (11312435423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145031185 + ... + 145031262.

It is an arithmetic number, because the mean of its divisors is an integer number (2030437136).

Almost surely, 2^11312435433 is an apocalyptic number.

11312435433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11312435433 is a deficient number, since it is larger than the sum of its proper divisors (4931061655).

11312435433 is a wasteful number, since it uses less digits than its factorization.

11312435433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 290062463.

The product of its digits is 12960, while the sum is 30.

Adding to 11312435433 its reverse (33453421311), we get a palindrome (44765856744).

The spelling of 11312435433 in words is "eleven billion, three hundred twelve million, four hundred thirty-five thousand, four hundred thirty-three".