Base | Representation |
---|---|
bin | 10000011101100011110… |
… | …000011111100101101110 |
3 | 11000010221202120001220222 |
4 | 100131203300133211232 |
5 | 122013300003234114 |
6 | 2223404502411342 |
7 | 144505300550114 |
oct | 20354360374556 |
9 | 4003852501828 |
10 | 1131250055534 |
11 | 3a684018a275 |
12 | 1632b1430b52 |
13 | 828a413c2b1 |
14 | 3ca77951ab4 |
15 | 1e65e20198e |
hex | 10763c1f96e |
1131250055534 has 8 divisors (see below), whose sum is σ = 1697051520840. Its totient is φ = 565566215256.
The previous prime is 1131250055491. The next prime is 1131250055539. The reversal of 1131250055534 is 4355500521311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×11312500555343 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131250055494 and 1131250055503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131250055539) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29382209 + ... + 29420684.
It is an arithmetic number, because the mean of its divisors is an integer number (212131440105).
Almost surely, 21131250055534 is an apocalyptic number.
1131250055534 is a deficient number, since it is larger than the sum of its proper divisors (565801465306).
1131250055534 is an equidigital number, since it uses as much as digits as its factorization.
1131250055534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58812514.
The product of its (nonzero) digits is 45000, while the sum is 35.
Adding to 1131250055534 its reverse (4355500521311), we get a palindrome (5486750576845).
The spelling of 1131250055534 in words is "one trillion, one hundred thirty-one billion, two hundred fifty million, fifty-five thousand, five hundred thirty-four".
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