Base | Representation |
---|---|
bin | 1010010010011110011000… |
… | …1101010010101011101000 |
3 | 1111001110120100111012001011 |
4 | 2210213212031102223220 |
5 | 2440321010322300230 |
6 | 40020521301433304 |
7 | 2245205400042415 |
oct | 244474615225350 |
9 | 44043510435034 |
10 | 11312511134440 |
11 | 367167768973a |
12 | 132853510b834 |
13 | 6409c426a599 |
14 | 2b175814910c |
15 | 1493e7400e2a |
hex | a49e6352ae8 |
11312511134440 has 16 divisors (see below), whose sum is σ = 25453150052580. Its totient is φ = 4525004453760.
The previous prime is 11312511134417. The next prime is 11312511134501. The reversal of 11312511134440 is 4443111521311.
It can be written as a sum of positive squares in 2 ways, for example, as 11141963609764 + 170547524676 = 3337958^2 + 412974^2 .
It is a super-2 number, since 2×113125111344402 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141406389141 + ... + 141406389220.
Almost surely, 211312511134440 is an apocalyptic number.
11312511134440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11312511134440 is an abundant number, since it is smaller than the sum of its proper divisors (14140638918140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312511134440 is a wasteful number, since it uses less digits than its factorization.
11312511134440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 282812778372 (or 282812778368 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 11312511134440 its reverse (4443111521311), we get a palindrome (15755622655751).
The spelling of 11312511134440 in words is "eleven trillion, three hundred twelve billion, five hundred eleven million, one hundred thirty-four thousand, four hundred forty".
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