Base | Representation |
---|---|
bin | 10101000100100100… |
… | …00011011100011001 |
3 | 1002012101121102021201 |
4 | 22202102003130121 |
5 | 141132004420111 |
6 | 5110311434201 |
7 | 550223211646 |
oct | 124222033431 |
9 | 32171542251 |
10 | 11312576281 |
11 | 4885721aa6 |
12 | 2238685961 |
13 | 10b3909826 |
14 | 7945d8dcd |
15 | 4632346c1 |
hex | 2a2483719 |
11312576281 has 2 divisors, whose sum is σ = 11312576282. Its totient is φ = 11312576280.
The previous prime is 11312576257. The next prime is 11312576291. The reversal of 11312576281 is 18267521311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8960326281 + 2352250000 = 94659^2 + 48500^2 .
It is a cyclic number.
It is not a de Polignac number, because 11312576281 - 27 = 11312576153 is a prime.
It is a super-2 number, since 2×113125762812 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11312576281.
It is not a weakly prime, because it can be changed into another prime (11312576291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656288140 + 5656288141.
It is an arithmetic number, because the mean of its divisors is an integer number (5656288141).
Almost surely, 211312576281 is an apocalyptic number.
It is an amenable number.
11312576281 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312576281 is an equidigital number, since it uses as much as digits as its factorization.
11312576281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 37.
The spelling of 11312576281 in words is "eleven billion, three hundred twelve million, five hundred seventy-six thousand, two hundred eighty-one".
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