Base | Representation |
---|---|
bin | 10000011101100100100… |
… | …101110111000001100001 |
3 | 11000010222201212211002000 |
4 | 100131210211313001201 |
5 | 122013312043421103 |
6 | 2223410122314213 |
7 | 144505530504144 |
oct | 20354445670141 |
9 | 4003881784060 |
10 | 1131264045153 |
11 | 3a6848074940 |
12 | 1632b6058969 |
13 | 828a6cc9a88 |
14 | 3ca7975405b |
15 | 1e660566aa3 |
hex | 10764977061 |
1131264045153 has 64 divisors (see below), whose sum is σ = 1881697305600. Its totient is φ = 665872721280.
The previous prime is 1131264045073. The next prime is 1131264045173. The reversal of 1131264045153 is 3515404621311.
1131264045153 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 2 + 640 + 4 + 5 + 1 + 5 + 3 = 666.
It is not a de Polignac number, because 1131264045153 - 29 = 1131264044641 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1131264045173) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1065501 + ... + 1843317.
It is an arithmetic number, because the mean of its divisors is an integer number (29401520400).
Almost surely, 21131264045153 is an apocalyptic number.
It is an amenable number.
1131264045153 is a deficient number, since it is larger than the sum of its proper divisors (750433260447).
1131264045153 is a wasteful number, since it uses less digits than its factorization.
1131264045153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 777979 (or 777973 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 36.
Adding to 1131264045153 its reverse (3515404621311), we get a palindrome (4646668666464).
The spelling of 1131264045153 in words is "one trillion, one hundred thirty-one billion, two hundred sixty-four million, forty-five thousand, one hundred fifty-three".
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