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1131264045173 is a prime number
BaseRepresentation
bin10000011101100100100…
…101110111000001110101
311000010222201212211002202
4100131210211313001311
5122013312043421143
62223410122314245
7144505530504203
oct20354445670165
94003881784082
101131264045173
113a6848074959
121632b6058985
13828a6cc9aa2
143ca79754073
151e660566ab8
hex10764977075

1131264045173 has 2 divisors, whose sum is σ = 1131264045174. Its totient is φ = 1131264045172.

The previous prime is 1131264045073. The next prime is 1131264045227. The reversal of 1131264045173 is 3715404621311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 856396623889 + 274867421284 = 925417^2 + 524278^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131264045173 - 218 = 1131263783029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131264045073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565632022586 + 565632022587.

It is an arithmetic number, because the mean of its divisors is an integer number (565632022587).

Almost surely, 21131264045173 is an apocalyptic number.

It is an amenable number.

1131264045173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131264045173 is an equidigital number, since it uses as much as digits as its factorization.

1131264045173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 38.

Adding to 1131264045173 its reverse (3715404621311), we get a palindrome (4846668666484).

The spelling of 1131264045173 in words is "one trillion, one hundred thirty-one billion, two hundred sixty-four million, forty-five thousand, one hundred seventy-three".